要求:从两个不同的表中获取各自的4条数据,然后整合(array_merge)成一个数组,再根据数据的创建时间降序排序取前4条。 遇到这个要求的时候就不是 ORDER BY 能解决的问题了。因此翻看 PHP 手册查找到了如下方法,做此笔记。 废话少说,奉上代码,清单如下: 1, 'name' => '张三', 'age' => 25, ), array( 'id' => 2, 'name' => '李四', 'age' => 23, ), array( 'id' => 3, 'name' => '王五', 'age' => 40, ), array( 'id' => 4, 'name' => '赵六', 'age' => 31, ), array( 'id' => 5, 'name' => '黄七', 'age' => 20, ), ); $sort = array( 'direction' => 'SORT_DESC', //排序顺序标志 SORT_DESC 降序;SORT_ASC 升序 'field' => 'age', //排序字段 ); $arrSort = array(); foreach($arrUsers AS $uniqid => $row){ foreach($row AS $key=>$value){ $arrSort[$key][$uniqid] = $value; } } if($sort['direction']){ array_multisort($arrSort[$sort['field']], constant($sort['direction']), $arrUsers); } var_dump($arrUsers); /* 输出结果: array (size=5) 0 => array (size=3) 'id' => int 5 'name' => string '黄七' (length=6) 'age' => int 20 1 => array (size=3) 'id' => int 2 'name' => string '李四' (length=6) 'age' => int 23 2 => array (size=3) 'id' => int 1 'name' => string '张三' (length=6) 'age' => int 25 3 => array (size=3) 'id' => int 4 'name' => string '赵六' (length=6) 'age' => int 31 4 => array (size=3) 'id' => int 3 'name' => string '王五' (length=6) 'age' => int 40 */